Question

An expression for the electric field that was produced by a spherically symmetric distribution is 4.04×103r2...

An expression for the electric field that was produced by a spherically symmetric distribution is 4.04×103r2 [^(r)] N/C.

A 37.0 cm diameter spherical surface shares its center with the spherical electric field. What is the flux through this spherical surface?
What is the charge inside the spherical surface?

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Homework Answers

Answer #1

Part A

From gauss's law, electric flux through gaussian surface is given by:

E = electric field by spherical distribution = 4.04*10^3*r^2

So,

So electric flux through spherical surface will be from r = 0, to r = R

R = radius of sphere = 37.0/2 = 18.5 cm = 0.185 m

4.04*10^3*0.185^3/3

8.53 Wb = electric flux

Part B.

Now electric flux inside spherical surface is given by:

Qenc = Charge inside closed surface = ?

= 8.85*10^-12

So,

Qenc =

Qenc = 8.53*8.85*10^-12

Qenc = 7.55*10^-11 C = Charge inside cylindrical surface

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