An expression for the electric field that was produced by a spherically symmetric distribution is 4.04×103r2 [^(r)] N/C.
A 37.0 cm diameter spherical surface shares its center with the
spherical electric field. What is the flux through this spherical
surface?
What is the charge inside the spherical surface?
Part A
From gauss's law, electric flux through gaussian surface is given by:
E = electric field by spherical distribution = 4.04*10^3*r^2
So,
So electric flux through spherical surface will be from r = 0, to r = R
R = radius of sphere = 37.0/2 = 18.5 cm = 0.185 m
4.04*10^3*0.185^3/3
8.53 Wb = electric flux
Part B.
Now electric flux inside spherical surface is given by:
Qenc = Charge inside closed surface = ?
= 8.85*10^-12
So,
Qenc =
Qenc = 8.53*8.85*10^-12
Qenc = 7.55*10^-11 C = Charge inside cylindrical surface
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