11. A proton accelerates from rest in a uniform electric field of 650 N/C. At one later moment, its speed is 1.10 Mm/s (nonrelativistic because v is much less than the speed of light).
(a) Find the acceleration of the proton.
m/s2
(b) Over what time interval does the proton reach this speed?
s
(c) How far does it move in this time interval?
m
(d) What is its kinetic energy at the end of this interval?
J
here,
electric feild , E = 650 N/C
final speed , v = 1.1 * 10^6 m/s
a)
the accelration , a = e * E /mp
a = ( 1.6 * 10^-19 * 650 )/(1.67 * 10^-27)
a = 6.23 * 10^10 m/s^2
b)
let the time taken be t
v = u + a * t
1.1 * 10^6 = 0 + 6.23 * 10^10 * t
solving for t
t = 1.76 * 10^-5 s
c)
the distance travelled , s = v^2 / ( 2 a)
s = (1.1 * 10^6)^2 /( 2 * 6.23 * 10^10) m
s = 9.7 m
d)
the kinetic energy at the end of this interval , KE = 0.5 m * v^2
KE = 0.5 * 1.67 * 10^-27 * ( 1.1 * 10^6)^2 J
KE = 1.01 * 10^-15 J
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