Question

The potential across the plates of a parallel-plate capacitor is 100 Volts and the separation between...

The potential across the plates of a parallel-plate capacitor is 100 Volts and the separation between the plates is 0.02 m. The charge on the plates are +50 nC and -50 nC, respectively. How much energy is needed to slowly pull the plates apart so that the distance between the plates is now 0.06 m? Assume that the area of the plates and the charge on each plate do not change.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A parallel plate capacitor of capacitance Co has plates of area A with separation d between...
A parallel plate capacitor of capacitance Co has plates of area A with separation d between them. When it is connected to a battery of voltage Vo, it has charge of magnitude Qo on its plates. It is then disconnected from the battery and the plates are pulled apart to a separation 2d without discharging them. After the plates are 2d apart, by what factor does the magnitude of the charge on the plates change? By what factor does the...
A parallel-plate capacitor with plate separation d is connected to a battery that provides a potential...
A parallel-plate capacitor with plate separation d is connected to a battery that provides a potential difference ε. While still connected to the battery, the plate separation is increased to 2d. a) Does the potential difference across the capacitor change as the separation increases? If so, then by what factor? If not, then why not? b) Does the capacitance change as the separation increases? If so, then by what factor? If not, then why not? c) Does the capacitor charge...
A parallel plate capacitor is made from two plates 7 cm^2 in area, with a plate...
A parallel plate capacitor is made from two plates 7 cm^2 in area, with a plate separation of 3 mm. The capacitor is fully charged across a 30 V battery, and then disconnected. How much charge is on the capacitor? Now material with a dielectric constant of 30 is inserted to fill the space between the plates, (with the battery disconnected), What is the charge on the capacitor? What is the energy stored in the capacitor? What the field between...
A parallel-plate capacitor has plates with an area of 0.012 m2 and a separation of 0.009...
A parallel-plate capacitor has plates with an area of 0.012 m2 and a separation of 0.009 m. The space between the plates is filled with a dielectric whose dielectric constant is 2. What is the potential difference between the plates when the charge on the capacitor plates is 5 ?C? (in kV)
A parallel plate capacitor is charged to 100 volts DC and it's plates are 1 mm...
A parallel plate capacitor is charged to 100 volts DC and it's plates are 1 mm apart, each with an area of 40x40 mm. The material between the plates has a dielectric constant of 5. Find the electric field between the plates and the value of the capacitor in microfarads.
1 A parallel plate capacitor is connected to a battery and becomes fully charged the capacitor...
1 A parallel plate capacitor is connected to a battery and becomes fully charged the capacitor is then disconnected and the separation between the plates is halved in such a way that so charge leaks off As the plate separation is being halved which of the following parameters remains constant? An air filled k=1 ideal parallel plate capacitor has a capacitance of C. If the area of the plates is doubled insert a dielectric material k=2 and the distance between...
A water-filled parallel plate capacitor has a plate area of 2.2 cm2 and plate separation of...
A water-filled parallel plate capacitor has a plate area of 2.2 cm2 and plate separation of 2.5 mm. The potential difference between its plates is held at 7.0 V. Calculate the magnitude of the electric field between its plates, the charge stored on each plate, and the charge stored on each plate after water is replaced by air. (a) the magnitude of the electric field between its plates -------------V/m (b) the charge stored on each plate ----------- nC (c) the...
A water-filled parallel plate capacitor has a plate area of 2.2 cm2 and plate separation of...
A water-filled parallel plate capacitor has a plate area of 2.2 cm2 and plate separation of 2.5 mm. The potential difference between its plates is held at 7.0 V. Calculate the magnitude of the electric field between its plates, the charge stored on each plate, and the charge stored on each plate after water is replaced by air. (a) the magnitude of the electric field between its plates -------------V/m (b) the charge stored on each plate ----------- nC (c) the...
A parallel-plate vacuum capacitor has 8.76 J of energy stored in it. The separation between the...
A parallel-plate vacuum capacitor has 8.76 J of energy stored in it. The separation between the plates is 3.70 mm . If the separation is decreased to 1.35 mm , a)what is the energy now stored if the capacitor was disconnected from the potential source before the separation of the plates was changed? b)What is the energy now stored if the capacitor remained connected to the potential source while the separation of the plates was changed?
A parallel-plate vacuum capacitor has 7.92 J of energy stored in it. The separation between the...
A parallel-plate vacuum capacitor has 7.92 J of energy stored in it. The separation between the plates is 3.50 mm . If the separation is decreased to 1.90 mm , A. what is the energy now stored if the capacitor was disconnected from the potential source before the separation of the plates was changed? U =? B. What is the energy now stored if the capacitor remained connected to the potential source while the separation of the plates was changed?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT