Question

a 20 kg block of ice is heated from -20 degrees Celsius to -2 degrees Celsius. how much heat does it absorbed during the heating

Answer #1

Mass of ice m = 20 kg

Initial temperature t = -20 ^{o} C

Final temeprature t ' = -2^{o} C

Specific heat of ice c = 2000 J / kg ^{o} C

Heat absorbed Q = mc ( t ' - t )

= 20(2000)(18)

= 720000 J

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