Question

8.00 g of aluminum at 200∘C and 19.0 g of copper are dropped into 50.0 cm3 of ethyl alcohol at 15.0∘C. The temperature quickly comes to 25.0 ∘C.

What was the initial temperature of the copper in ∘C?

Answer #1

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Quantity of heat loss by aluminium = **m x c x
dT**

= 0.008* 913*(200 - 25) = **1278.2
J**

.

Quantity of heat loss by copper = **m x c x dT**

= 0.019* 385*(T - 25) = **7.315 T - 182.875 J**

Mass of ethyl alcohol = volume * density

= 0.000050 m^3 *789 = 0.03945 kg.

Quantity of heat gained by ethyl = **mc dT**

= 0.03945 * 2500*(25 - 15) = **986.25 J**

heat lost = Heat gained

1278.2 J + 7.315 T - 182.875 J = 986.25 J

7.315 T = -109.075

**T = - 14.91 ˚C**

**This shows that copper also gains heat.**

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