Consider atmospheric conditions as follows: temperature of 30 C, normal atmospheric pressure and a humidity of 80%.
A) What is the moisture content of the air?
B) What is the partial pressure of water vapor in the atmosphere?
Moisture content = actual vapour pressure =Saturation vapour density x RH/100
Moisture content = 30.4 x 80/100 (Saturation vapour density at 300 = 30.4 g/m3)
Moisture content = 24.32 g/m3
(B) Number of moles of water per m3 = 24.32/18 = 1.35 mol/m3
Ideal gas eqn
PV = nRT
P = nRT/V
P = 1.35 x 8.314 x (273 + 30) (n/V = 1.35 as calculated earlier)
P = 3403.64 Pa
P = 0.0336 atm --Ans (1 atm = 1.01 x 105 Pa)
Get Answers For Free
Most questions answered within 1 hours.