In winter a lake has a 0.20 m thick ice layer over 1.50 m of water. A light beam from above strikes a spot on the ice, making a 33 degree angle with the normal.
How far horizontally from that spot does the light ray strike the lake bottom?
1*sin(33) = 1.31sinr
r = sin^-1(sin33/1.31) = 24.57 degrees
tan(24.57) = d/0.2
displacement in the ice d = 0.091 m
again use snells law
ice to water surface
1.31sin(24.57) = 1.33sinr'
r' = 24.17 degrees
displacement in water d' = 1.5tan(24.17) = 0.673 m
total displacement D = d+d' = 0.091+0.673 = 0.764 m
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