A pendulum clock uses a rock fastened to a very thin steel wire.
This clock is designed so that one "tick" of the clock (one
complete period of the pendulum) is equal to precisely 14.6 s. The
clock is then heated by 11.2°C. Will it now run "fast" or "slow"?
Find the new value of the period of the clock. Assume the thermal
expansion coefficients of the rock are both zero.
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