Dylan thinks that conductance is equal to the slope of the I-versus-ΔVgraph at a particular point; Finn thinks resistance is equal to the ratio between the ΔV and I values at that point.
For which types of circuit element are Dylan and Finn correct?
Only Finn's method is correct for circuit elements that produce a straight line through the origin for II versus ΔV (Ohmic elements). If the curve of II versus ΔV is not straight (non-Ohmic elements), then both Dylan and Finn are correct. |
Both Dylan and Finn are correct for circuit elements that produce a straight line through the origin for II versus ΔV(Ohmic elements). If the curve of II versus ΔV is not straight (non-Ohmic elements), then only Finn's method is correct. |
Only Dylan's method is correct for circuit elements that produce a straight line through the origin for II versus ΔV(Ohmic elements). If the curve of II versus ΔV is not straight (non-Ohmic elements), then both Dylan and Finn are correct. |
Both Dylan and Finn are correct for circuit elements that produce a straight line through the origin for II versus ΔV(Ohmic elements). If the curve of II versus ΔV is not straight (non-Ohmic elements), then only Dylan's method is correct. |
The correct answer would be option. B) Both Dylan and Finn are correct for circuit elements that produce a straight line through the origin for I versus ΔV(Ohmic elements). If the curve of II versus ΔV is not straight (non-Ohmic elements), then only Finn's method is correct.
Usually from the I-versus-ΔVgraph its slope given us,
G = I/ΔV which is equal to the conductor of the wire or we can say that reciprocal of the resistance but this will be possible when graph will be linear
And also, resistance is equal to the ratio between the ΔV and I values at that point and this is correct either for linear or non linear graph. In case of non ohmic or non linear graph usually we takepick a point on the curve. Draw a line tangent to the non-linear curve at that point. The slope of that line is R, where R is the resistance at that point.
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