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6. A convex (converging) lens has a focal length of 17.5 cm. Where on the lens...

6. A convex (converging) lens has a focal length of 17.5 cm. Where on the lens axis should an object be placed in order to get a virtual, enlarged image with a magnification of 2.80? cm

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Answer #1

6.

f = focal length of convex lens = 17.5 cm

di = image distance

do = object distance

m = magnification = 2.80

magnification is given as

m = - di/do

2.80 = - di/do

di = - 2.80 do                                                                 eq-1

Using the lens equation

1/f = 1/di + 1/do

1/17.5 = 1/(- 2.80 do) + 1/do

do = 11.25 cm

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