A 10.0 cm long wire has a 1.50mm diameter and is made of a newly discovered metal called Oaktonium. This metal has 9.3x10^29 free electrons per cubie meter and these electrons have a mean time between collisions of 3.2 x 10^-14 s. The wire is connected to a 1.0 V battery.
Calculate the current through the wire.
I know the answer is 1.481465 x 10^4. I just don't know how to get that. Need the steps
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