Question

20.1 A short circular coil with 15 turns has a radius of 7 cm. The coil is placed is a 2.5 T magnetic field. Find the flux through the coil for each case: a) the plane of the coil is perpendicular to the magnetic field b) the angle between the plane of the coil and the magnetic field is 35o.

Answer 1

here,

number of turns , N = 15 turns

radius ,r = 7 cm =0.07 m

magnetic feild , B = 2.5 T

a)

when the plane of the coil is perpendicular to the magnetic feild

the flux through the loop , phi = N * pi * r^2 * B  

Phi = 15 * pi * 0.07^2 * 2.5 T.m^2

phi = 0.58 T.m^2

b)

theta = 35 degree

when the angle between the plane of the coil and the magnetic field is 35 degree

the flux through the loop , phi = N * pi * r^2 * B * sin(theta)

Phi = 15 * pi * 0.07^2 * 2.5 * sin(35) T.m^2

phi = 0.33 T.m^2