Question

At most, how many bright fringes can be formed on either side of the central bright fringe when light of wavelength 619 nm falls on a double slit whose slit separation is 3.08 × 10-6 m?

Answer 1

Solution:

Using a double slit whose slit separation,

dSin = m

m = dSin/

For find maximum number of bright fringes Substitute = 90^o

m = 3.08*10^-6 *sin90^o/619*10^-9

= 4.9757

= 5.

The great number of bright fringes = 5 .

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