A 12.0-g piece of clay is launched horizontally at a 105-g wooden block that is initially at rest on a frictionless horizontal surface and connected to a spring having spring constant 45 N/m. The piece of clay sticks to the side of the block. If the clay-block system compresses the spring by a maximum of 16.0 cm, what was the speed of the piece of clay at impact with the block?
here,
mass of clay, m = 0.012 kg
mass of woooden block , mw = 0.105 kg
spring constant , k = 45 N/m
compression in the spring , x = 0.16m
let the initial velocity of the bullet be u
using conservation of momentum for block and bullet
m * u = ( M + m ) * v
v = u *m / ( M + m)
and for the spring
0.5 * k * x^2 = 0.5 * (M + m) * v^2
0.5 * k * x^2 = 0.5 * (M + m) * (u *m / ( M + m))^2
k * x^2 = ((u *m )^2/ ( M + m))
45 * 0.16^2 = ((u *0.012 )^2/ ( 0.105 + 0.012))
u = 30.6 m/s
the initial speed of the clay before impact is 30.6 m/s
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