Question

You throw a ball vertically upward with an initial velocity of 10 m/s from a window located 20 m above the ground. Knowing that the acceleration of the ball is constant and equal to 9.81 m/s^2 downward (this makes for negative acceleration as upward motion is positive and downward motion is negative and gravity pulls downward), determine:

(a) The acceleration at t = 2 s

(b) The equation for velocity (Because you are looking for an equation for velocity, you cannot use the constant acceleration equations. Keep your integration boundaries generic with v final = vf and time final = tf while beginning conditions are vo= 10 m/s and t0 = 0 sec)

(c) The velocity of the ball at t = 3 s (Now you can plug t = 3 into the above generic equation.)

(d) The equation for position (Again, keep your integral nonspecific and useful for any time by using the upper bounds of tf and sf while starting bounds are t = 0 and s = 20 m.)

(e) What is the highest elevation that the ball reaches?

(f) How long does it take for the ball to reach the peak?

(g) How long does it take for the ball to hit the ground?

Answer #1

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