Question

A converging lens (f_{1} = 12.7 cm) is located 30.6 cm
to the left of a diverging lens (f_{2} = -6.48 cm). A
postage stamp is placed 33.9 cm to the left of the converging lens.
Locate the final image of the stamp relative to the diverging
lens.

Answer #1

for converging lens :

f_{1} = 12.7 cm

d_{o1} = 33.9 cm

d_{i1} = ?

using the lens equation

1/d_{i1} + 1/d_{o1} = 1/f_{1}

1/d_{i1} + 1/33.9 = 1/12.7

d_{i1} = 20.3 cm

for diverging lens :

D = distance between the lens = 30.6 cm

d_{o2} = object distance for diverging lens = D -
d_{i1} = 30.6 - 20.3 = 10.3 cm

f_{2} = - 6.48 cm

d_{i2} = image distance for diverging lens = ?

using the lens

1/d_{o2} + 1/d_{i2} = 1/f_{2}

1/10.3 + 1/d_{i2} = 1/(-6.48)

d_{i2} = - 4 cm

image is 4 cm to the left of diverging lens

A converging lens (f = 11.3 cm) is located 24.0 cm to
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