Question

A converging lens (f_{1} = 12.7 cm) is located 30.6 cm
to the left of a diverging lens (f_{2} = -6.48 cm). A
postage stamp is placed 33.9 cm to the left of the converging lens.
Locate the final image of the stamp relative to the diverging
lens.

Answer #1

for converging lens :

f_{1} = 12.7 cm

d_{o1} = 33.9 cm

d_{i1} = ?

using the lens equation

1/d_{i1} + 1/d_{o1} = 1/f_{1}

1/d_{i1} + 1/33.9 = 1/12.7

d_{i1} = 20.3 cm

for diverging lens :

D = distance between the lens = 30.6 cm

d_{o2} = object distance for diverging lens = D -
d_{i1} = 30.6 - 20.3 = 10.3 cm

f_{2} = - 6.48 cm

d_{i2} = image distance for diverging lens = ?

using the lens

1/d_{o2} + 1/d_{i2} = 1/f_{2}

1/10.3 + 1/d_{i2} = 1/(-6.48)

d_{i2} = - 4 cm

image is 4 cm to the left of diverging lens

A converging lens (f = 11.3 cm) is located 24.0 cm to
the left of a diverging lens (f = -5.42 cm). A postage
stamp is placed 46.0 cm to the left of the converging lens.
(a) Locate the final image of the stamp relative
to the diverging lens. (b) Find the overall
magnification.

A converging lens (f = 14.2 cm) is located 23.2 cm to the left
of a diverging lens (f = -4.59 cm). A postage stamp is placed 37.1
cm to the left of the converging lens. (a) Locate the final image
of the stamp relative to the diverging lens. (b) Find the overall
magnification.

A converging lens (f = 11.0 cm) is located 23.6 cm to the left
of a diverging lens (f = -4.51 cm). A postage stamp is placed 52.7
cm to the left of the converging lens. (a) Locate the final image
of the stamp relative to the diverging lens. (b) Find the overall
magnification.

A converging lens (f1 = 11.9 cm) is located 27.6 cm
to the left of a diverging lens (f2 = -5.94 cm). A
postage stamp is placed 34.8 cm to the left of the converging lens.
Find the overall magnification.

A converging lens (f1 = 24.0 cm) is located
56.0 cm to the left of a diverging lens (f2 =
−28.0 cm). An object is placed to the left of the converging lens,
and the final image produced by the two-lens combination lies 22.1
cm to the left of the diverging lens. How far is the object from
the converging lens?

A converging lens (f1 = 24.0 cm) is located 56.0 cm to the left
of a diverging lens (f2 = -28.0 cm). An object is placed to the
left of the converging lens, and the final image produced by the
two-lens combination lies 21.1 cm to the left of the diverging
lens. How far is the object from the converging lens?

A converging lens (f1 = 24.0 cm) is located 56.0 cm to the left
of a diverging lens (f2 = -28.0 cm). An object is placed to the
left of the converging lens, and the final image produced by the
two-lens combination lies 19.4 cm to the left of the diverging
lens. How far is the object from the converging lens?

A converging lens (f1 = 24.0 cm) is located 56.0 cm to the left
of a diverging lens (f2 = -28.0 cm). An object is placed to the
left of the converging lens, and the final image produced by the
two-lens combination lies 20.0 cm to the left of the diverging
lens. How far is the object from the converging lens?

A converging lens (f1 = 24.0 cm) is located
56.0 cm to the left of a diverging lens (f2 =
-28.0 cm). An object is placed to the left of the converging lens,
and the final image produced by the two-lens combination lies 20.7
cm to the left of the diverging lens. How far is the object from
the converging lens (including units)?

8.A diverging lens (f1 = −10.5 cm) is located 43.0 cm to the
left of a converging lens (f2 = 23.5 cm). A 3.0-cm-tall object
stands to the left of the diverging lens, exactly at its focal
point. Determine the distance of the final image relative to the
converging lens (including proper algebraic sign

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 1 minute ago

asked 7 minutes ago

asked 8 minutes ago

asked 11 minutes ago

asked 13 minutes ago

asked 18 minutes ago

asked 28 minutes ago

asked 28 minutes ago

asked 29 minutes ago

asked 35 minutes ago

asked 41 minutes ago

asked 41 minutes ago