Question

A converging lens has a focal length of 93.0 cm. Locate the
images for the following object distances, if they exist. Find the
magnification. (Enter 0 in the *q* and *M* fields if
no image exists.)

(a) 93.0 cm

q |
= cm |

M |
= |

Select all that apply to part (a).

real

virtual

upright

inverted

no image

(b) 11.6 cm

q |
= cm |

M |
= |

Select all that apply to part (b).

real

virtual

upright

inverted

no image

(c) 837 cm

q |
= cm |

M |
= |

Select all that apply to part (c).

real

virtual

upright

inverted

no image

Answer #1

(a) distance of the object (d_{o}) =93 cm

hence the object is at the focus therefore the image will be at
infinity

so q = 0 , M= 0

and no image will be seen

(b) distance of the object (d_{o}) = 11.6 cm

from the lens formula

1/d_{o} + 1/q = 1/f

where q is image distance

1/q = 1/f - 1/d_{o}

1/q = (1/93 )- (1/11.6)

q = -13.25 cm

Magnification (M) = -(q/d_{o}) = -(-13.25/11.6)

M = 1.14

hence the image will be virtual and upright

(c)

distance of the object (d_{o}) = 837 cm

1/d_{o} + 1/q = 1/f

1/q = 1/f - 1/d_{o}

1/q = (1/93 )- (1/837)

q = 104.625 cm

M = - (q/d_{o}) = -(104.625/837)

M = -0.125

therfore the image will be real and inverted.

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