Two lenses are placed along the x axis, with a diverging lens of focal length −7.40 cm on the left and a converging lens of focal length 15.0 cm on the right. When an object is placed 14.0 cm to the left of the diverging lens, what should the separation s of the two lenses be if the final image is to be focused at x = ∞?
for the final image to be focused at infinity,the image from the diverging lens should form at a distnace equal to focal length of the converging lens=15 cm
Given focal length of diverging lens=f=-7.4 cm
object distance of the object from diverging lens=u=14 cm
Let the image distnace be v
Per lens formula,
1/f=1/u+1/v
1/-7.4=1/14+1/v
v=-4.84 cm
negative value of v means the image is formed at the object side of the diverging lens
let the separation between the converging and diverging lens be s
s+4.84=15
s=10.159 cm
Therefore, the separation should be 10.159 cm
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