Question

An egg is launched off the top of lynnwood hall. The initial velocity off the egg is Vo=Vot and the initial height off the egg above the ground is H

(a)What is the velocity off the egg at the momentum it hits the ground in terms of Vo, H and g?

(b)What is the speed of the egg at the moment it hits the ground in terms of Vo, H and g?

(c)What angle does the egg make with the ground as it hits the ground in term of Vo, H and g?

Answer 1

a)

Along X-direction :

V_ox = initial velocity along the x-direction = V_ot

a_x = acceleration = 0 m/s²

t = time taken

V_fx = final velocity

using the equation

V_fx = V_ox + a_x t

V_fx = V_ot + (0) t

V_fx = V_ot  

Along the Y-direction :

V_oy = initial velocity along the y-direction = 0

a_y = acceleration = g

Y = displacement = H

V_fy = final velocity

using the equation

V²_fy = V²_oy + 2 a_y Y

V²_fy = 0²+ 2(g) H

V_fy = sqrt(2gH)

velocity is given as

V_f = V_ot i + sqrt(2gH) j

b)

speed is given as

final velocity is given as

|V_f | = sqrt(V_fx² + V_fy²)

V_f = sqrt(V²_ot + 2gH)

c)

= tan^-1(2gH/V_ot)