In an LRC series circuit, the inductance is 244 mH, the resistance is 29 Ω, and the capacitance is 354 μF. If the AC voltage applied across the circuit is given by
V(t) = (12 V)sin(11πt)
calculate the voltage across each element at a time of t = 0.04 s.
VR | = | V |
VC | = | V |
VL | = | V |
here given
V(t) = 12 sin 11 pi t
W = 11pi = 11*3.14 = 34.54 rad/s
inductance reactance XL = WL
XL = 34.54 *0.244 = 8.42 ohms
Capactivie reactance Xc = 1/wC
Xc = 1/(34.54 * 354*10^-6)
Xc = 81.78 ohms
impedence Z^2 = R^2 + (Xc-xL)^2
Z^2 = 29^2 + (81.78 -8.42)^2
Z = 78.88 ohms
Voltage at t= 0.04 sec is
V 12* sin(11*3.14 * 0.04)
V = 0.289 Volts
Current I = V/Z = 0.289/78.88 = 3.6 mA
Vr = I R = 0.0036* 29 = 0.106 Volts
VL = iXL = 0.0036 * 8.42 = 0.0303 Volts
Vc = iXc = 0.0036 * 81.78 = 0.294 Volts
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