A vertical straight wire carrying an upward 29 A current exerts an attractive force per unit length of 7.1×10−4 N/m on a second parallel wire 7.5 cm away.
What current (magnitude and direction) flows in the second wire?
We are using the formula for this particular question as shown in image-
Where = 4 x 10- 7 T m/A.
Than as per the question-
7.1 * 10-4 = ( 4 x 10- 7 ) (29 * I2) / (2 * 7.5 *10-2)
7.1 * 10-4 = ( 58 x 10- 5 ) * (I2) / 7.5
I2 = (7.1*7.5) * 10 / 58
I2 = 9.18 A
For diretion, go with uploaded image-
Direction in wire 2 will bw upward.
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