Question

The tires of a car make 45 revolutions as the car reduces its speed uniformly from 120 km/h to 50 km/h. The tires have a diameter of 0.80 m.

(a) What was the angular acceleration of the tires?

____ rad/s^{2}

(b) If the car continues to decelerate at this rate, how much more
time is required for it to stop?

____s

Answer #1

The tires of a car make 68 revolutions as the car reduces its
speed uniformly from 91.0 km/h to 60.0 km/h. The tires have a
diameter of 0.80 m.
What was the angular acceleration of the tires?
If the car continues to decelerate at this rate, how much more
time is required for it to stop?
If the car continues to decelerate at this rate, how far does it
go? Find the total distance.

The tires of a car make 56 revolutions as the car reduces its
speed uniformly from 93 km/h to 50 km/h . The tires have a diameter
of 0.76 m .
A)What was the angular acceleration of the tires?
B)If the car continues to decelerate at this rate, how much more
time is required for it to stop?

The tires of a car make 61 revolutions as the car reduces its
speed uniformly from 93.0 km/h to 63.0 km/h. The tires have a
diameter of 0.80 m.
Part A What was the angular acceleration of the
tires?
Part B If the car continues to decelerate at
this rate, how much more time is required for it to stop?
Part C If the car continues to decelerate at
this rate, how far does it go? Find the total distance.

The tires of a car make 74 revolutions as the car reduces its
speed uniformly from 86 km/h to 43 km/h . The tires have a diameter
of 0.81 m .What was the angular acceleration of the tires?If the
car continues to decelerate at this rate, how much more time is
required for it to stop?

The tires of a car make 77 revolutions as the car reduces its
speed uniformly from 87.0 km/h to 55.0 km/h. The tires have a
diameter of 0.90 m.
A) What was the angular acceleration of the tires?
B) If the car continues to decelerate at this rate, how much
more time is required for it to stop?
C) If the car continues to decelerate at this rate, how far does
it go? Find the total distance.

The tires of a car make 62 revolutions as the car reduces its
speed uniformly from 95.0 km/h to 59.0 km/h . The tires have a
diameter of 0.84 m. A) What was the angular acceleration of the
tires? B) If the car continues to decelerate at this rate, how much
more time is required for it to stop? C) How far does the car go?
Find the total distance.

The tires of a car make 70 revolutions as the car reduces its
speed uniformly from 94.0 km/h to 62.0 km/h. The tires have a
diameter of 0.86 m. If the car continues to decelerate at this
rate, how far does it go? Find the total distance.

An car traveling at 110.0 km/h has tires of 67.0 cm diameter. If
the car is brought to a stop uniformly in 45.0 complete turns of
the tires (without skidding), what is the magnitude of the angular
acceleration of the wheels?
A.
14.7 rad/s2
B.
9.7 rad/s2
C.
10.7 rad/s2
D.
-14.7 rad/s2

1. A dentist using a dental drill brings it from rest to maximum
operating speed of 364,000 rpm in 3.2 s. Assume that the drill
accelerates at a constant rate during this time.
(a) What is the angular acceleration of the drill in
rev/s2?
rev/s2
(b) Find the number of revolutions the drill bit makes during
the 3.2 s time interval.
rev
2. In a laundromat, during the spin-dry cycle of a washer, the
rotating tub goes from rest to...

An car traveling at 110.0 km/h has tires of 67.0 cm diameter. If
the car is brought to a stop uniformly in 45.0 complete turns of
the tires (without skidding), what is the magnitude of the angular
acceleration of the wheels?

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