Question

How much energy (J) is contained in 1.1 kg of water if its natural deuterium is...

How much energy (J) is contained in 1.1 kg of water if its natural deuterium is used in the fusion reaction of 21H+21H?31H+ 11H?

Compare to the energy obtained from the burning of 1.1 kg of gasoline, about 5.5×107 J .

Homework Answers

Answer #1

mass on left = 2 (2.014101778) u

mass on right = 3.016049282 + 1.0078250322 u

mass diff = mass on left - mass on right

= 4.33 x 10^-3 u


Energy released by this reaction = delta(m) c^2

= (4.33 x 10^-3)(1.66 x 10^-27)(3 x 10^8)^2


and number of reaction can happen in 1kg of water

= n NA

= (1.1 / (18 x 1.66 x 10^-27 kg))


Energy obtained = (1.1 / (18 x 1.66 x 10^-27))((4.33 x 10^-3)(1.66 x 10^-27)(3 x 10^8)^2)

= 2.3815 x 10^13 J .....Ans

ratio = (2.3815 x 10^13)/(5.5 x 10^7)

= 4.33 x 10^5 times more

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