Question

A system with 20,000 molecules has two energy levels (A and B). At first, energy level...

A system with 20,000 molecules has two energy levels (A and B). At first, energy level A is populated by 60% of the molecules. After a reversible process, energy level A is populated by 90% of the molecules and the system is at 373 K.

a. What is the difference in energy between the two levels? Provide your answer in J/mol.
b. What is the change in the total energy of the system?
c. What is the change in entropy?
Hint: After the reversible process, the system should reach equilibrium and follows the Boltzmann distribution.

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
a system has two non-degenerate energy levels. energy gap is 0.1eV. calculate the probability that the...
a system has two non-degenerate energy levels. energy gap is 0.1eV. calculate the probability that the system is in the higher energy level, when it is in thermal equilibrium with a heat reservoir of absolute temperature i- 300K ii-600K iii-1000K iv- 10000K at what temperature is the probability equal to (v) 0.25 (vi) 0.4 (vii) 0.49
Suppose that a molecle has just two energy levels. The ground state is singly degenerate and...
Suppose that a molecle has just two energy levels. The ground state is singly degenerate and the excited state is triply degerate. If the enrgy difference between the two states (on a molar basis) is 52 kJ/mol at what temperature will the two states be equally populated? QUANTUM CHEMISTRY
Consider an isolated system containing two blocks of copper with equal mass. One block is initially...
Consider an isolated system containing two blocks of copper with equal mass. One block is initially at 0oC while the other is at 100oC.They are brought into contact with each other and allowed to thermally equilibrate. What is the entropy change for the system during this process? The heat capacity for copper is Cp = 24.5 [J/mol k]
A system contains two energy levels separated by 300 cm–1 . (a) What are the relative...
A system contains two energy levels separated by 300 cm–1 . (a) What are the relative populations of the upper and lower levels if the temperature is 1 K? What if the temperature is 1×105 K? (b) What is the temperature of the system when the population of the upper energy state is half that of the lower energy state?
1. A molecule has a ground state and two excited electronic energy levels all of which...
1. A molecule has a ground state and two excited electronic energy levels all of which are not degenerate. The energies of the three states are E = 0, E1 = 1x10^-20 J and E2 = 2x10^-20 J. Calculate the partition functions at 298 and 1000K. What fraction of the molecules is in each of the three states at these temperatures?
Diamond a. At 298 K, what is the Gibbs free energy change G for the following...
Diamond a. At 298 K, what is the Gibbs free energy change G for the following reaction? Cgraphite ->  Cdiamond b. Is the diamond thermodynamically stable relative to graphite at 298 K? c. What is the change of Gibbs free energy of diamond when it is compressed isothermally from 1 atm to 1000 atm at 298 K? d. Assuming that graphite and diamond are incompressible, calculate the pressure at which the two exist in equilibrium at 298 K. e....
In a two level system, where the ground state has energy zero, and the other state...
In a two level system, where the ground state has energy zero, and the other state has energy +1.00 kcal/mol, 2/3 of the particles are found to be in the ground state. What can we say about the entropies of each of these two states? Can we find both exactly? Is there a relationship between them?
± Free Energy and Chemical Equilibrium The equilibrium constant of a system, K, can be related...
± Free Energy and Chemical Equilibrium The equilibrium constant of a system, K, can be related to the standard free energy change, ΔG, using the following equation: ΔG∘=−RTlnK where T is standard temperature in kelvins and R is equal to 8.314 J/(K⋅mol). Under conditions other than standard state, the following equation applies: ΔG=ΔG∘+RTlnQ In this equation, Q is the reaction quotient and is defined the same manner as K except that the concentrations or pressures used are not necessarily the...
The equilibrium constant of a system, K, can be related to the standard free energy change,...
The equilibrium constant of a system, K, can be related to the standard free energy change, ΔG∘, using the following equation: ΔG∘=−RTlnK where T is a specified temperature in kelvins (usually 298 K) and R is equal to 8.314 J/(K⋅mol). Under conditions other than standard state, the following equation applies: ΔG=ΔG∘+RTlnQ In this equation, Q is the reaction quotient and is defined the same manner as K except that the concentrations or pressures used are not necessarily the equilibrium values....
The equilibrium constant of a system, K, can be related to the standard free energy change,...
The equilibrium constant of a system, K, can be related to the standard free energy change, ΔG∘, using the following equation: ΔG∘=−RTlnK where T is a specified temperature in kelvins (usually 298 K) and R is equal to 8.314 J/(K⋅mol). Under conditions other than standard state, the following equation applies: ΔG=ΔG∘+RTlnQ In this equation, Q is the reaction quotient and is defined the same manner as K except that the concentrations or pressures used are not necessarily the equilibrium values....
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT