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An athlete at the gym holds a 3.2 kg steel ball in his hand. His arm...

An athlete at the gym holds a 3.2 kg steel ball in his hand. His arm is 66 cm long and has a mass of 4.0 kg. What is the magnitude of the torque about his shoulder if he holds his arm in each of the following ways?

(a) Straight out to his side, parallel to the floor
____ N m

(b) Straight, but 35° below horizontal
____ N m

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Answer #1

The torque due to a force is given by

where is the angle between the force and the line joining force to point of rotation

we have two forces here, the weight of the arm (W1 ) acting at the center of mass of arm, the weight of steel ball (W2 ) at the extreme end of the arm

b) As shown in the diagram

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