Question

Two point Charges, q and -q, are separated by a distance d, both being located at a distance d/2 from the infinite conducting plane. What is the magnitude of the electric force action on each charge? Find the magnitude of the electric field at the midpoint between these charges?

Reference: In this instance the Conducting plate Separates -q and q (which is d distance apart above the conducting plate). The conducting plate is d/2 distance below the charges -q and q.

Answer #1

F = force by charge "q" at D = k q^{2} /BD^{2} =
k q^{2} /(sqrt(2) d) = k q^{2} /(2
d^{2})

F' = force by charge "- q" at A and C = k
q^{2}/d^{2}

Net force is given as

F_{net} = sqrt(F'^{2} + F'^{2}) - F =
sqrt(2) k q^{2}/d^{2} - (0.5)k q^{2}
/(d^{2}) = (0.91) k q^{2}/d^{2}

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