Question

A system consists of 56 electrons and 44 protons. e=1.60×10^?19C. Is the total charge of the system positive or negative?What is the total charge of the system?

and

In case 1 a charge q is at the origin, and a charge 5q is 1 m away. In case 2 a charge q is at the origin, and a charge ?5q is 1 m away.Is the magnitude of the force exerted on the charge at the origin in case 1 greater than, less than, or equal to the magnitude of the force exerted on that charge in case 2? PLEase answer quick

Answer #1

Part A

Charge of proton = + 1.6*10^-19

Charge of electron = - 1.6*10^-19

No. of proton = 44

No. of electron = 56

Net charge will be

Q = Np*Qp + Ne*Qe

Q = 44*1.6*10^-19 + 56*(-1.6*10^-19)

**Q = -19.2*10^-19 C**

**Also total charge is negative.**

Part B

Magnitude of electrostatic force is given by:

|F| = k|q1|*|q2|/r^2

In case 1

r = 1 m

|F| = k*|q|*|5q|/1^2

|F| = k*5*q^2

In case 2

r = 1 m

|F| = k*|q|*|-5q|/1^2

we know that

|-5q| = 5q

|F| = k*5*q^2

So Force will be equal in both cases.

Please Upvote.

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