Question
A vectors who tail is at the origin, and whose head is at (-3, -4, 15)N,...
A vectors who tail is at the origin, and whose head is at (-3, -4, 15)N, what are the directional angles that describe the direction of this vector?
Homework Answers
Answer #1
A = (0, 0, 0)
B = (-3, -4, 15)
AB = <-3, -4, 15> - <0, 0, 0>
AB = <-3, -4, 15>
Direction angles are given by:
cos 
= a/sqrt (a^2 +
b^2 + c^2)
= arccos [a/sqrt
(a^2 + b^2 + c^2)]
cos 
= b/sqrt (a^2 +
b^2 + c^2)
= arccos [b/sqrt
(a^2 + b^2 + c^2)]
cos 
= c/sqrt (a^2 +
b^2 + c^2)
= arccos [c/sqrt
(a^2 + b^2 + c^2)]
here a = -3, b = -4, and c = 15
So,
= arccos
[(-3)/sqrt (9 + 16 + 225)] = 100.93 deg
= arccos
[(-4)/sqrt (9 + 16 + 225)] = 104.65 deg
= arccos
[(15)/sqrt (9 + 16 + 225)] = 18.43 deg
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