Question

A transformer has 1600 turns on its secondary and 200 turns on its primary. The primary is connected to a 20V ac source. What is the output voltage of the secondary in volts?

Answer #1

Given:

Number of turns on the primany of transformer = n_{1} =
200 turns

Number of turns on the secondary of transformer = n_{2}
= 1600 turns

Primary voltage = V_{1} = 20 V

To find: Secondary voltage = V_{2}= ?

We know that for an ideal transformer,

Voltage ratio = Turns ratio

(V_{1} / V_{2}) = (n_{1} /
n_{2})

_{V2} =
V_{1} x (n_{2 }/ n_{1})

_{V2} = 20 x
[1600/200 ]

= 20 x 8

_{V2} = 160
V

**The output voltage of the secondary is 160
volts.**

Since n_{2} is greater then n_{1} then
V_{2} is greater than V_{1} and the device is
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