A 4.1-kg ball is thrown from the top of a 4-m tall building (point A) with a speed of 1 m/s at an angle 2 degrees above the horizontal. If air resistance is negligible, what is the value of the kinetic energy of the ball as it hits the ground?
Gravitational acceleration = g = 9.81 m/s^{2}
Mass of the ball = m = 4.1 kg
Height of the building = H = 4 m
Initial velocity of the ball = V_{1} = 1 m/s
Angle at which the ball is thrown = = 2^{o}
Kinetic energy of the ball as it hits the ground = E
By conservation of energy the potential energy and kinetic energy of the ball initially is equal to the kinetic energy of the ball as it hits the ground.
mgH + mV_{1}^{2}/2 = E
E = (4.1)(9.81)(4) + (4.1)(1)^{2}/2
E = 162.934 J
Value of kinetic energy of the ball as it hits the ground = 162.934 J
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