Unpolarized light passes through three polarizers. The axis of transmission of the first polarizer is vertical, the second has a transmission axis rotated 30.0o with respect to the first, and the third has a transmission axis rotated 75.0o relative to the first. If the initial light intensity of the beam is Io, calculate the light intensity after the beam passes through... a)The second polarizer b)The third polarizer |
Initial intensity of the beam = Io
When an unpolarized light passes through a polariser intensity reduced to half, then intensity I = Io / 2
so, after first polarizer Intensity of beam, I1 = Io / 2
When a polarized light passes through a polariser that is
vertical, then intensity, I = Iinitial *
cos2
here is the angle
between two polarizer,
a) so, Intensity of beam after second polariser, I2 =
I1*cos21
= I0/2 * cos2 (30)
= 3/4 * I0/2
= 3/8 I0
b)In this case angle 2 will
be angle between second and third polariser, so
,
2 =
75-30 = 45 degree
so, Intensity of beam after second polariser, I3 =
I2*cos22 =
3/8 I0 * cos2(45) =3/8 * 1/2 *
Io
= 3/16 Io
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