(each plate is a circular disk of diameter 20 cm)
Set up the plate separation at 2 cm
# |
d |
Electrometer reading (V) |
1/V |
C=kε0A/d |
1 |
2mm |
100 |
0.01 |
|
2 |
3mm |
90 |
0.011 |
|
3 |
4mm |
80 |
0.0125 |
|
4 |
5mm |
70 |
0.143 |
|
5 |
6mm |
60 |
0.016 |
2. plot a graph with C along y-axis and 1/V along the x-axis.
3. What is the value of slope and what physical quantity it gives?
here Area A = pi r^2
r = D/2 = 20cm/2 = 10 cm = 0.1 m
A = 3.14 * 0.1^2 = 0.0314^2
and now
for d = 2 mm = 0.002 m ,
C = eoA/d = (8.85*10^-12* 0.0314)/(0.002)
C =138.9 pF
------------------
for d = 3 mm, C =(8.85*10^-12* 0.0314)/(0.003) = 92.63 pF
for d = 4mm, C = (8.85*10^-12* 0.0314)/(0.004) = 69.47 pF
for d = 5 mm, C = (8.85*10^-12* 0.0314)/(0.005) = 55.57 pF
for d= 6 mm, C = (8.85*10^-12* 0.0314)/(0.006) = 46.315 pF
this plot will be linear
and this plot of C vs 1/V gives CV = Constant = charge Q
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