Question

The work done on a system is time dependent, where W(t) = (2.00 J/s)t + (0.500 J/s3)t3. (a) What is the instantaneous power at t = 0.665s and (b) t = 1.16s? Now let us assume that we know the instantaneous power to be P(t) = (3.50 J/s2)t + (1.50 J/s3)t2. Assuming that there is no work done on the system at t = 0, what is work done at (c) t = 0.865s and (d) t = 1.25s?

Answer #1

Instantaneous power is given as dW/dt. As given that

**(a)** at t= 0.665s

**(b)** at t= 1.16s

Now Given that

**(c)** at t=0.865 s

**(d)** at t= 1.25 s

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