Question

1) A cardinal (Richmondena cardinalis) of mass 4.20×10−2 kg and a baseball of mass 0.140 kg...

1) A cardinal (Richmondena cardinalis) of mass 4.20×10−2 kg and a baseball of mass 0.140 kg have the same kinetic energy. What is the ratio of the cardinal's magnitude pc of momentum to the magnitude pb of the baseball's momentum?

2) A man weighing 750 N and a woman weighing 460 N have the same momentum. What is the ratio of the man's kinetic energy Km to that of the woman Kw?

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Homework Answers

Answer #1

1) Mc,Vc = cardinal's mass and velocity
Mb,Vb = baseball's mass and velocity

(Mc)(Vc)² = (Mb)(Vb)²
(Mc)/(Mb) = (Vb/Vc)²
(Vb/Vc) = √(Mc/Mb)

(McVc)(Vc) = (MbVb)(Vb)

(McVc)/(MbVb) = (Vb/Vc) = √(Mc/Mb) = √(.042/0.140) ≈ 0.548

The cardinal's momentum is approximately 0.548 of the baseball's momentum

2) mass x vel = momentum
750 x Vm = 460 x Vw
Vm = 460/750 x Vw
Km = 0.5 x 750 x [460/750 Vw]^2 = 0.5 x 460^2/750 x Vw^2
Kw = 0.5 x 460 x Vw^2
Km/Kw = 460/750 = 0.613 to 1

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