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The horizontal coordinates of a Frisbee™ in a strong wind are given by x = -12t...

The horizontal coordinates of a Frisbee™ in a strong wind are given by x = -12t + 4t 2 and y = 10t – 3t 2 , where x and y are in meters, and t is in seconds. What is the magnitude of acceleration of the Frisbee at t = 1.0s? a) 2 m/s2 b) 10 m/s2 c) 5.7 m/s2 d) 10.6 m/s2

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