A helicopter, starting from rest, accelerates straight up from the roof of a hospital. The lifting force does work in raising the helicopter. An 790-kg helicopter rises from rest to a speed of 7.0 m/s in a time of 4.0 s. During this time it climbs to a height of 7.3 m. What is the average power generated by the lifting force?
According to the concept of the work energy and power
the avrage power P=(mgh+1/2mv^2)/t
Given that
mass m=790 kg
initial speed u=0
finial speed v=7 m/s
time t=4s
height h=7 m/s
now we find the average power gentrated by lifting force
basing on the concept of the work energy therom
Wnet=1/2mv^2-1/2mu^2
-Wg+Wf=1/2mv^2-1/2mu^2
Wf=12/mv^2-1/2mu^2+Wg
Wf=1/2mv^2-1/2mu^2+mgh
Wf=1/2mv^2+mgh
the average power P=Wf/t=1/2mv^2+mgh/t
=(0.5*790*7^2+790*9.8*7.3)/4
=18967.9 W
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