In the figure, a conducting rod of length L = 35.0 cm moves in a magnetic field B? of magnitude 0.490 T directed into the plane of the figure. The rod moves with speed v = 6.00 m/s in the direction shown.
When the charges in the rod are in equilibrium, what is the magnitude E of the electric field within the rod?
What is the magnitude Vba of the potential difference between the ends of the rod?
What is the magnitude E of the motional emf induced in the rod?
Question1---------------
when the rod is in motion charges experience magnetic force in
presence of magnetic field and
according to Force(magnetic) = q*[cross product of velocity and
field]
if velocity is on -ve y-axis and field inside the plane then by
Right hand Screw rule positive charges experience force towards
point P and negative charges accumulate at point A and hence
naturally their is attractive coulombic force between charges so in
steady condition these forces balance each other and Hence
q*v*B = q*E
E = v*B
E = 6.00*0.490 = 2.94V/m Ans.1
Question2-----------------
emf V = E*d
d = 33cm = 0.35m
V = 2.94*0.35
V = 1.029V Ans.2
Question3--------------
It is same as question1
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