Question

After a shipwreck, a solid steel spoon lies at the bottom of the ocean, 6.20 km...

After a shipwreck, a solid steel spoon lies at the bottom of the ocean, 6.20 km below the surface.

A.) What's the water pressure at that depth?

B.) Find the fractional volume change in the spoon due to compression forces.

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Answer #1

After a shipwreck, a solid steel spoon lies at the bottom of the ocean, 6.20 km below the surface.
A- What is the water pressure at that depth?
B- Find the fractional volume change in the spoon due to compression forces

A) ?p = ?*g*?h = 1027kg/m³ * 9.8m/s² * 6200m = 6.240*10^7 Pa
If you have different values for ? and g, use them.

B) fractional volume change = ?V / V = ?p / k
?V / V = 6.240*10^7Pa / 160*10^9Pa = 0.00039
Again, if you have a bulk modulus k for steel that is different, use it.

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