Question

A 0.5 kg ball traveling at 5 m/s bounces off a stationary 10 kg pot of...

A 0.5 kg ball traveling at 5 m/s bounces off a stationary 10 kg pot of baba ganoush. The ball rebounds straight back at 5 m/s. Assume no friction.

Please show the equations needed for each question to be solved.

A) What is the velocity of the pot of baba ganoush?
B) If the ball was in contact with the pot for 0.1 seconds, what was the force on the pot?

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Homework Answers

Answer #1

A) The initial momentum of ball taveling at 5 m/s in the positive direction

After collision, the ball travels at 5 m/s but in the negative direction. And baba ganoush travels at speed v. Hence the final momentum of the ball+bab ganoush is

By conservation of momentum initial momentum is equal to final momentum

Therefore

This gives

Solving this gives

Therefore the velocity of the pot of baba ganoush is

B) Initially, the pot baba ganoush is at rest which means its initial momentum is zero. The change in momentum of the baba ganoush is

The force on the pot is

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