Question

A nylon string on a tennis racket is under a tension of 215 N .

Part A If its diameter is 1.10 mm , by how much is it lengthened from its untensioned length of 29.0 cm ? Use ENylon=5.00×109N/m2.

Answer 1

Young's modulus of nylon = E = 5 x 10⁹ N/m²

Tension in the nylon string = T = 215 N

Diameter of the nylon string = D = 1.1 mm = 1.1 x 10^-3 m

Cross-sectional area of the nylon string = A

A = D²/4

A = (1.1x10^-3)²/4

A = 9.503 x 10^-7 m²

Initial length of the nylon string = L = 29 cm = 0.29 m

Amount the nylon string extends by = L

Stress in the nylon string = = T/A

Strain in the nylon string = = L/L

L = 1.31 x 10^-2 m

Amount the nylon string stretches = 1.31 x 10^-2 m