Question

Earth’s equatorial radius is about 6378 km. What is the centripetal acceleration experienced by a person...

Earth’s equatorial radius is about 6378 km. What is the centripetal acceleration experienced by a person standing at the Equator due to Earth’s rotation? (Answer using SI units)

Imagine the same person standing at the Equator of planet X, which has the same radius and mass as the Earth, but a shorter, 8-hour long day. What is the centripetal acceleration experience by this person? Based on your calculations, how does the person’s weight differ between the two locations?

The Earth orbits the Sun at an average distance of 149.6 x 106 km. The orbit is nearly circular. The period of one revolution is 365.26 days. Find the average centripetal acceleration of planet Earth in its orbit around the Sun.

The London Eye, one of the largest Ferris Wheels, was recently built near the bank of the river Thames in London. It has a diameter of 394 feet and it takes 30 minutes for a complete rotation. What is the centripetal force experienced by a 150 lb person sitting in one of the passenger capsules?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The London Eye, one of the largest Ferris Wheels, was recently built near the bank of...
The London Eye, one of the largest Ferris Wheels, was recently built near the bank of the river Thames in London. It has a diameter of 394 feet and it takes 30 minutes for a complete rotation. What is the centripetal force experienced by a 150 lb person sitting in one of the passenger capsules? Please answer correctly, thank you so much in advance!
The radius of the Earth’s orbit around the sun (assumed to be circular) is 1.50∙108 km,...
The radius of the Earth’s orbit around the sun (assumed to be circular) is 1.50∙108 km, and the Earth travels around this obit in 365 days. The mass of the Earth is 5.97∙1024 kg. magnitude of the orbital velocity of the Earth: 2.98.104 m/s acceleration of the earth toward the sun: 5.91.10-3 m/s2 a) What is the magnitude of centripetal force acting on the Earth? b) What is responsible for providing this centripetal force? c) Calculate the gravitational acceleration OF...
The radius of the Earth’s orbit around the sun (assumed to be circular) is 1.50∙10^8 km,...
The radius of the Earth’s orbit around the sun (assumed to be circular) is 1.50∙10^8 km, and the Earth travels around this obit in 365 days. The mass of the Earth is 5.97∙10^24 kg. (a)What is the magnitude of the orbital velocity of the Earth, in m/s? (b)What is the magnitude of centripetal force acting on the Earth? (c)Calculate the gravitational acceleration OF the Earth (not ON the Earth). Hint: think of your answer to part (d), and set two...