A refrigerator has a coefficient of performance of 2.25, runs on an input of 135 W of electrical power, and keeps its inside compartment at 5∘C. If you put a dozen 1.0-L plastic bottles of water at 31∘C into this refrigerator, how long will it take for them to be cooled down to 5∘C? (Ignore any heat that leaves the plastic.) A refrigerator has a coefficient of performance of 2.25, runs on an input of 135 W of electrical power, and keeps its inside compartment at 5∘C. Answer with a unit of minutes. Please answer legibly.
Coefficient of performance of the refrigerator = COP = 2.25
Input power of the refrigerator = P = 135 W
Volume of the plastic bottle = V = 1 L = 0.001 m3
Number of plastic bottles = n = 12
Density of water = = 1000 kg/m3
Mass of the water = M
M = nV
M = (12)(1000)(0.001)
M = 12 kg
Initial temperature of the water = T1 = 31 oC
Final temperature of the water = T2 = 5 oC
Specific heat of water = C = 4186 J/(kg.oC)
Amount of heat to be extracted from the water = Q
Q = MC(T1 - T2)
Q = (12)(4186)(31 - 5)
Q = 1306032 J
Time taken to coll the water = T
Work to be supplied to the refrigerator to extract Q amount of heat = W
W = PT = 135T
T = 4299.69 sec
T = 71.66 minutes
Time taken to cool down the water to 5 oC by the refrigerator = 71.66 minutes
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