Question

mike tyson's punch starts from rest and accelerates uniformly at 100 m/s^2 while moving 50 cm....

mike tyson's punch starts from rest and accelerates uniformly at 100 m/s^2 while moving 50 cm. the speed of his hand immediately before landing on his opponent's jaw is

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A 1.50 ✕ 103-kg car starts from rest and accelerates uniformly to 16.0 m/s in 12.9...
A 1.50 ✕ 103-kg car starts from rest and accelerates uniformly to 16.0 m/s in 12.9 s. Assume that air resistance remains constant at 400 N during this time. (a) Find the average power developed by the engine. ____ hp (b) Find the instantaneous power output of the engine at t = 12.9 s, just before the car stops accelerating. ______ hp
A 1.50 ✕ 103-kg car starts from rest and accelerates uniformly to 15.1 m/s in 12.7...
A 1.50 ✕ 103-kg car starts from rest and accelerates uniformly to 15.1 m/s in 12.7 s. Assume that air resistance remains constant at 400 N during this time. (a) Find the average power developed by the engine. (hp) (b) Find the instantaneous power output of the engine at t = 12.7 s, just before the car stops accelerating. (hp)
A car accelerates uniformly from rest and reaches a speed of 21.0 m/s in 9.05 s....
A car accelerates uniformly from rest and reaches a speed of 21.0 m/s in 9.05 s. Assume the diameter of a tire is 59.0 cm. (a) Find the number of revolutions the tire makes during this motion, assuming that no slipping occurs. rev (b) What is the final angular speed of a tire in revolutions per second? rev/s
a) A car accelerates uniformly from rest and reaches a speed of 13.7 m/s in 10.9...
a) A car accelerates uniformly from rest and reaches a speed of 13.7 m/s in 10.9 s. The diameter of a tire is 71.8 cm. Find the number of revolutions the tire makes during this motion, assuming no slipping. Answer in units of rev. b) What is final rotational speed of a tire? Answer in units of rev/s.
A merry-go-round starts from rest and accelerates uniformly over 19.5 s to a final angular velocity...
A merry-go-round starts from rest and accelerates uniformly over 19.5 s to a final angular velocity of 6.25 rev/min. (a) Find the maximum linear speed of a person sitting on the merry-go-round 4.00 m from the center. (b) Find the person's maximum radial acceleration. (c) Find the angular acceleration of the merry-go-round. (d) Find the person's tangential acceleration.
A merry-go-round starts from rest and accelerates uniformly over 26.5 s to a final angular velocity...
A merry-go-round starts from rest and accelerates uniformly over 26.5 s to a final angular velocity of 6.90 rev/min. (a) Find the maximum linear speed of a person sitting on the merry-go-round 7.25 m from the center. (b) Find the person's maximum radial acceleration. (c) Find the angular acceleration of the merry-go-round. (d) Find the person's tangential acceleration.
A merry-go-round starts from rest and accelerates uniformly over 10.0 s to a final angular velocity...
A merry-go-round starts from rest and accelerates uniformly over 10.0 s to a final angular velocity of 4.55 rev/min. (a) Find the maximum linear speed of a person sitting on the merry-go-round 6.00 m from the center. (b) Find the person's maximum radial acceleration. (c) Find the angular acceleration of the merry-go-round. (d) Find the person's tangential acceleration.
A 3.00 kg block starts from rest at the top of a 30° incline and accelerates...
A 3.00 kg block starts from rest at the top of a 30° incline and accelerates uniformly down the incline, moving 1.83 m in 1.80 s. (a) Find the magnitude of the acceleration of the block. m/s2 (b) Find the coefficient of kinetic friction between the block and the incline. (c) Find the magnitude of the frictional force acting on the block. N (d) Find the speed of the block after it has slid a distance 1.83 m. m/s
A car starts from rest at a stop sign. It accelerates at 3.6 m/s^2 for 6.5...
A car starts from rest at a stop sign. It accelerates at 3.6 m/s^2 for 6.5 s, coasts for 1.7 s, and then slows down at a rate of 2.5 m/s^2 for the next stop sign. How far apart are the stop signs?
A merry-go-round starts from rest and accelerates uniformly over 14.5 s to a final angular velocity...
A merry-go-round starts from rest and accelerates uniformly over 14.5 s to a final angular velocity of 7.65 rev/min. (a) Find the maximum linear speed of a person sitting on the merry-go-round 4.25 m from the center. (b) Find the person's maximum radial acceleration. (c) Find the angular acceleration of the merry-go-round. (a) Find the maximum linear speed of a person sitting on the merry-go-round 4.25 m from the center. (b) Find the person's maximum radial acceleration. (c) Find the...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT