A particle of mass 0.2g carries a charge 10^-8C. It was given an initial horizontal velocity ?? = (5 × 10^4 ??) in +x direction. What are the magnitude and direction of the minimum magnetic field that will cancel gravitational effects? Neglect Earth’s magnetic field.
gravitational force acts down wards -z direction
gravitational force Fg = m*g (-k)
magnetic force = Fb
Fb + Fg = 0
Fb = -Fg
magnetic force Fb must act along +z direction ( upward)
magnetic force Fb = q*( V X B ) k
B = Bxi + Byj + Bzk
Fb = q*( vxi X (Bxi + Byj + Bzk )
Fb = q*vx*By ( i X j ) + q*vx*Bz ( i X k )
Fb = q*vx*By k - q*vx*Bz j
Fb is along +K
magnitude of Fb
Fb = q*vx*By
magnetic field is along +y direction
Fb = Fg
q*Vx*By = m*g
10^-8*5*10^4*By = 0.2*10^-3*9.8
minimum magnetic field By = 3.92 T
magnetic field is along +y direction
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