Question

A car accelerates uniformly from rest to 17.9 m/s in 6.31 s along a level stretch...

A car accelerates uniformly from rest to 17.9 m/s in 6.31 s along a level stretch of road. Ignoring friction, determine the average power required to accelerate the car if (a) the weight of the car is 8.28 x 103 N, and (b) the weight of the car is 1.58 x 104 N.

Homework Answers

Answer #1

Here, we have to find power required for two different cases in both cases we have given the weight of the car but other values like velocity and time are same. To calculate energy first we have to find kinetic energy and for kinetic energy, we need mass which is missing in question. Mass is calculated with the help of weight of the car.

Formula's used

1) Power (P)= Energy(E)/Time(t)

2) Energy(E)= 1/2*m*v^2 Where m= mass and v= velocity

3) Force(F)= m*g Where g= Gravitational constant (9.8)

Given

t= 6.31sec

v= 17.9 m/s

(a) Weight of car i.e. Force= 8.28*103N

F=mg

8.28*103=m*9.8

m= 87kg

Now energy

E=1/2m.v^2

E= 1/2*87*(17.9)^2= 13937.8J

Power, P= E/t

P=13937.8/6.31 = 2208.8W

(b )Weight of car i.e. Force= 1.58*104N

F=mg

1.58*104=m*9.8

m= 16.7kg

Now energy

E=1/2m.v^2

E= 1/2*16.7*(17.9)^2= 2675.4J

Power, P= E/t

P=2675.4/6.31 = 423.9W

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
a car accelerates uniformly from rest to 24.1 m/s in 9 s along a level stretch...
a car accelerates uniformly from rest to 24.1 m/s in 9 s along a level stretch of road. Ignoring friction , determine the average power required to accelerate the car if the mass of the car is 1,131 kg
A 1.50 ✕ 103-kg car starts from rest and accelerates uniformly to 16.0 m/s in 12.9...
A 1.50 ✕ 103-kg car starts from rest and accelerates uniformly to 16.0 m/s in 12.9 s. Assume that air resistance remains constant at 400 N during this time. (a) Find the average power developed by the engine. ____ hp (b) Find the instantaneous power output of the engine at t = 12.9 s, just before the car stops accelerating. ______ hp
A 1.50 ✕ 103-kg car starts from rest and accelerates uniformly to 15.1 m/s in 12.7...
A 1.50 ✕ 103-kg car starts from rest and accelerates uniformly to 15.1 m/s in 12.7 s. Assume that air resistance remains constant at 400 N during this time. (a) Find the average power developed by the engine. (hp) (b) Find the instantaneous power output of the engine at t = 12.7 s, just before the car stops accelerating. (hp)
a 2500 kg car accelerates uniformly from rest to 15.0 m/s in 8.00 s. What is...
a 2500 kg car accelerates uniformly from rest to 15.0 m/s in 8.00 s. What is the work done on the car in this time interval? What is the power delivered by the engine in this time interval? Answer in 3 decimal places, and include full equation please
A car at the Indianapolis 500 accelerates uniformly from the pit area, going from rest to...
A car at the Indianapolis 500 accelerates uniformly from the pit area, going from rest to 330 km/h in a semicircular arc with a radius of 230 m A) Determine the tangential and radial acceleration of the car when it is halfway through the arc, assuming constant tangential acceleration. B) If the curve were flat, what would the coefficient of static friction would be necessary between the tires and the road to provide this acceleration with no slipping or skidding?
A 1,500 kg car starts from rest and accelerates to 23 m/s in 11 s. Assume...
A 1,500 kg car starts from rest and accelerates to 23 m/s in 11 s. Assume that the air resistance remains constant at 162 N. Calculate the acceleration of the car. Calculate the average force exerted by engine during this time. Calculate the average velocity of the car. Calculate the average power output during this time.
A car accelerates uniformly from rest and reaches a speed of 21.0 m/s in 9.05 s....
A car accelerates uniformly from rest and reaches a speed of 21.0 m/s in 9.05 s. Assume the diameter of a tire is 59.0 cm. (a) Find the number of revolutions the tire makes during this motion, assuming that no slipping occurs. rev (b) What is the final angular speed of a tire in revolutions per second? rev/s
a) A car accelerates uniformly from rest and reaches a speed of 13.7 m/s in 10.9...
a) A car accelerates uniformly from rest and reaches a speed of 13.7 m/s in 10.9 s. The diameter of a tire is 71.8 cm. Find the number of revolutions the tire makes during this motion, assuming no slipping. Answer in units of rev. b) What is final rotational speed of a tire? Answer in units of rev/s.
1.Imagine two balls colliding on a billiard table that is frictionless. Decide which statement is correct...
1.Imagine two balls colliding on a billiard table that is frictionless. Decide which statement is correct and explain why:(a) The total momentum of the system that contains only one of the two balls is the same before and after the collision.(b) The total momentum of the system that contains both of the two balls is the same before and after the collision. 2.One object is at rest, and another is moving. The two collide in one-dimensional, completely inelastic collision. In...
A jogger accelerates from rest to 3.04 m/s in 2.45 s. A car accelerates from 16.4...
A jogger accelerates from rest to 3.04 m/s in 2.45 s. A car accelerates from 16.4 to 28.4 m/s also in 2.45 s. (a) Find the magnitude of the acceleration of the jogger. (b) Determine the magnitude of the acceleration of the car. (c) How much further does the car travel than the jogger during the 2.45 s?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT