Question

How much heat is needed to convert 1 kg of ice at 0C to 1 kg of water vapor at 100C?

Answer 1

Converting 100. g of ice at 0.00 °C to water vapour at 100.00 °C requires 301 kJ of energy.

There are three heats to consider:

q1 = heat required to melt the ice to water at 0.00 °C.

q2 = heat required to warm the water from 0.00 °C to 100.00 °C.

q3 = heat required to vapourize the water to vapour at 100 °C.

q1=m?Hfus=100.g×334J1g = 33 400 J

q2=mc?T=100.g×4.184J1°C?g×100.00°C = 41 800 J

q3=m?Hvap=100.g×2260J1g = 226 000 J

q1+q2+q3 = 33 400 J + 41 800 J + 226 000 J = 301 000 J
= 301 kJ