Two experimental vehicles are being driven at a constant tangential acceleration. To test their braking ability, the drivers each press the brake as hard as they can at the same time. What is the final velocity of each vehicle? Assuming they both started at the same place, which vehicle traveled the furthest?
Final velocity for Vehicle A
Final velocity for Vehicle B
Numerical Answer for the vehicle that traveled the furthest.
Vehicle A |
Vehicle B |
|
Acceleration (Km/hr^2) |
50 |
55 |
Initial Speed (Km/hr) |
100 |
150 |
Time traveled before stop (hr) |
2 |
2 |
10 points - Solution 1: Final Speed (Km/hr) |
200 |
220 |
Solution for the furthest traveled vehical-
Vehical A)-
a = 0.003858 m/s2 U = 27.78 m/s t= 7200 sec
Than-
SA = Ut + 1/2at2
SA = (27.78)*(7200) + 1/2(0.003858)*(7200)2
SA = 200016 + 99999.36
SA = 300015.36 m
SA = 300.015 Km
Vehical B)-
a = 0.004243 m/s2 U = 41.67 m/s t= 7200 sec
SB = Ut + 1/2at2
SB = (41.67)*(7200) + 1/2(0.004243)*(7200)2
SB = 300024 + 109978.56
SB = 410002.56 m
SB = 410.002 Km
By comparing both the distance, we will get Vehical B will get further.
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