You pull downward with a force of 28N rope that passes over a disk-shaped pulley of mass 1.2kg and radius 0.075m. the other end of the rope is attached to a 0.67mkg mass. Is the tension in the rope the same on both sides of the pulley? If not whih side has the largest tension? (b) Find the tension in the rope on both sides of the pulley
a)
No,the tension in the rope on the other end of the rope accelerates the hanging mass, but the tension on your side
both imparts angular acceleration to the pulley and accelerates the hanging mass. Therefore, the rope on your side
of the pulley has the greater tension.
b)
T1 = 28 N
F = ma for the hanging mass
y = T2 - Mg = M
= I for the pulley
= rT1 - rT2 = I = (1/2mr^2)(a/r)
a = 2(T1 - T2) / m
T2 - Ma = M( 2(T1 - T2) / m)
T2 = M(2T1 + mg) / (2M + m)
T2 = 0.67(2*28 + 1.2*9.81) / (2*0.67 + 1.2)
T2 = 18 N
Get Answers For Free
Most questions answered within 1 hours.