Question

cholo

Answer 1

1) gauge pressure = rho*g*h

rho density of fluid = 1649 kg /m^3

h = depth = 31m

g = acceleration due to gravity = 9.8 m/s^2

gauge pressure = 1649*9.8*31 = 500966.2 pa <-------answer

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2) density = mass/volume

density = 24.5/4.59 = 5.34 grams/cm^3   <-------answer

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3) Fup = Mg - Fb

Fb = buoyancy force = rho*V*g = 1030*0.32^3*9.8 = 330.76 N

Fup = (1816*9.8) - (330.76) = 17466.04 N <-------answer

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4)

alfa = dL/(Lo*dT)

dL - alfa*Lo*dT

change in length dL = 0.0001*143*(36.3-4.8) = 0.45045 m    <-------answer

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5)

heat required = Q = m*S*dT = 0.2512*4190*(85.1-20) = 68519.5728 J   <-------answer

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6) here volume is constant

at constant volume

P2/P1 = T2/T1

P2 = P1*T2/T1

T1 = 273+20 = 293

T2 = 40+273 = 313K

P2 = (1*313)/293 = 1.07 atm <-------answer