Pellets of mass 2.0 g are fired in parallel paths with speeds of 130 m/s through a hole 2.5 mm in diameter. How far from the hole must you be to detect a 1.0-cm-diameter spread in the beam of pellets?
1 cm diameter spread = 0.5 cm = 0.005 m in radius
Diffraction angle is given as
Tan (theta) = 0.005 / d
where d is the distance between us and hole
Wavelength = h / mv = 6.63e-34 / 0.002*130 = 2.55e-33 m
As we have a circular aperture, we can use airy disc formula
sin (theta) = 1.22*wavelength / D ( where D is diameter of hole or aperture)
sin (theta) = 1.22*2.55e-33 / 0.0025
As the angle is very small, we can write
0.005 / d = 1.22*2.55e-33 / 0.0025
solve for d, we get
d = 4.02e27 m
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